There are no. of ways to find the nth highest value from the table.
In this post, I am sharing some of the ways to find out the same.
Lets first create a Salary table and populate some data in it.
create table tblSalary (salary INT) insert into tblSalary select 5000 union all select 5000 union all select 9000 union all select 8000 union all select 7000 union all select 7000 union all select 8000 union all select 3000
In the table, highest value is 9000 and 2nd highest value is 8000 which is duplicate so 3rd distinct highest value is 7000.
Now lets find out 3rd highest salary with different ways
declare @nHighest int set @nHighest = 3 --Set value here to get nth highest value -- Method 1 select min(salary) as salary from ( select distinct top (@nHighest) salary as salary from tblSalary order by salary desc ) tab -- Method 2 select top 1 (salary) from ( select distinct top (@nHighest) salary as salary from tblSalary order by salary desc ) tab order by salary -- Method 3 select distinct (a.salary) from tblSalary a where @nHighest = (select count (distinct (b.salary)) from tblSalary b where a.salary<=b.salary) -- Method 4 select distinct salary from ( select dense_rank() over (order by salary desc) as rnk, salary from tblSalary ) tab where rnk = @nHighestOUTPUT