Mar 30, 2011

Format Number in SQL Server

To format a number in custom format like 99,99,999.00 there is no inbuilt function prior to SQL Server 2012, however same is available in SQL Sever 2012 onwards.

In this article, I am sharing a user defined function to format the number in custom format for prior versions.

The function takes two parameters
  • Number to be formatted.  Ex : (123456789.99999)
  • Format. Ex : (99,99,99,9999,99)
and returns
  • formatted number as output Ex : (12,34,56,789.99)

      @pNumber NUMERIC(16, 5)
    , @pFormat VARCHAR(50)
    DECLARE   @lStr1      VARCHAR(50)
            , @lCtrS      SMALLINT
            , @lCtrE      SMALLINT
            , @lChr       CHAR
            , @lFormat    VARCHAR(50)
            , @lPosStr    SMALLINT
            , @lPosFormat SMALLINT
            , @lAfterDot  VARCHAR(10)
            , @lBeforeDot VARCHAR(50)
    SET @lStr1 = CAST(@pNumber AS VARCHAR)
    SET @lPosStr = Charindex('.', Reverse(@lStr1)) - 1
    SET @lPosFormat = Charindex('.', Reverse(@pFormat))
    IF @lPosFormat > 0
        SET @lPosFormat = @lPosFormat - 1
    IF @lPosStr < @lPosFormat
        SET @lAfterDot = RIGHT(@lStr1,@lPosStr)+Replicate('0', @lPosFormat-@lPosStr)
        SET @lAfterDot = LEFT(RIGHT(@lStr1, @lPosStr), @lPosFormat)
    IF @lPosStr > 0
        SET @lBeforeDot = Reverse(LEFT(@lStr1, Charindex('.', @lStr1) - 1))
        SET @lBeforeDot = Reverse(@lStr1)
    IF @lPosFormat > 0
        SET @lFormat = Reverse(Substring(@pFormat, 1, Charindex('.', @pFormat)- 1))
        SET @lFormat = Reverse(@pFormat)

    SET @lCtrS = 0
    SET @lCtrE = Len(@lFormat)
    WHILE @lCtrS < @lCtrE
        SET @lCtrS = @lCtrS + 1
        SET @lChr = Substring(@lFormat, @lCtrS, 1)
        IF @lChr = ',' AND Len(@lBeforeDot) >= @lCtrS
            SET @lBeforeDot = LEFT(@lBeforeDot, @lCtrS - 1) + ',' + Substring(@lBeforeDot, @lCtrS, 100)

    IF @lPosStr > 0 AND @lPosFormat > 0
        SET @lStr1 = Reverse(@lBeforeDot) + '.' + @lAfterDot
        SET @lStr1 = Reverse(@lBeforeDot)

    RETURN @lStr1
Let's test the function
SELECT dbo.fnFormat(12345.99, '99,999.99') as [Formatted Value]
SELECT dbo.fnFormat(1234567.99, '9,999,999.99') as [Formatted Value]
SELECT dbo.fnFormat(123456789.99, '99,99,99,999.99') as [Formatted Value]
SELECT dbo.fnFormat(123456789.99, '999,999,999.99') as [Formatted Value]

Mar 29, 2011

Hierarchy of Employees in Sql Server with CTE

In this post, I am sharing the solution to find the hierarchy of employees using recursive CTE.

The solution will list all the employees coming under the hierarchy of an employee.

create table #tblemployee  (
      empid   varchar(10) primary key
    , empname varchar(10)
    , mgrid   varchar(10)

insert into #tblemployee
select 'Emp001', 'Satish', NULL union all
select 'Emp002', 'Amit', 'Emp001'  union all
select 'Emp003', 'Sumit', 'Emp001' union all
select 'Emp004', 'Anil', 'Emp002' union all
select 'Emp005', 'Tarun', 'Emp003' union all
select 'Emp006', 'Sandeep', 'Emp003' union all
select 'Emp007', 'Abhay', 'Emp006' union all
select 'Emp008', 'Deepak', 'Emp002' union all
select 'Emp009', 'Suman', 'Emp007' union all
select 'Emp010', 'Raman', 'Emp007'

;with reportees as (
    select empid, empname, mgrid, 1 as level
    from   #tblemployee    
    where  mgrid = 'Emp001'
    union all
    select #tblemployee.empid, #tblemployee.empname, #tblemployee.mgrid, level + 1
    from   #tblemployee
    inner join reportees on #tblemployee.mgrid = reportees.empid

select  a.empid, a.empid, a.mgrid, b.empname as mgrname, level
from    reportees a
left join #tblemployee b on a.mgrid = b.empid
order by level

drop table #tblemployee

Mar 26, 2011

Convert Number to Roman Numerals in SQL Server

In this post, I am sharing small function to convert Number to Roman Numeral in SQL Server

CREATE FUNCTION fnConvertIntToRoman(@i INT)
    RETURN    Replicate('M', @i/1000)
                  Replicate('C', @i%1000/100),
                  Replicate('C', 9), 'CM'),
                  Replicate('C', 5), 'D'),
                  Replicate('C', 4), 'CD')
                  Replicate('X', @i%100 / 10),
                  Replicate('X', 9),'XC'),
                  Replicate('X', 5), 'L'),
                  Replicate('X', 4), 'XL')
                  Replicate('I', @i%10),
                  Replicate('I', 9),'IX'),
                  Replicate('I', 5), 'V'),
                  Replicate('I', 4),'IV')
Let's test the function
select dbo.fnConvertIntToRoman(1) as 'Roman Value'
select dbo.fnConvertIntToRoman(15) as 'Roman Value'
select dbo.fnConvertIntToRoman(118) as 'Roman Value'
select dbo.fnConvertIntToRoman(1008) as 'Roman Value'

Mar 11, 2011

Cumulative sum in Sql Server

There are numerous ways to compute cumulative sum in SQL Server.

In this post, we will see how to compute cumulative sum in SQL Server using Row_Number and self join.

NOTE: This would work on SQL Server 2005 onwards

Let's take an example where we will calculate student wise cumulative sum of marks.

First create a Marks table and populate some data in it

create table tblMarks (
    studid  varchar(20)
    , subcode varchar(20)
    , marks   int

insert into tblMarks
select 'Stud1', 'English', 60 union all
select 'Stud1', 'History', 70 union all
select 'Stud1', 'Maths', 80 union all
select 'Stud1', 'Science', 75 union all
select 'Stud2', 'English', 55 union all
select 'Stud2', 'History', 60 union all
select 'Stud2', 'Maths', 57 union all
select 'Stud2', 'Science', 65
Now let write query to calculate cumulative sum for all subjects student wise

;with cte as (
    select row_number() over (order by studid, subcode) as rownum,*
    from tblMarks
select a.studid, a.subcode, a.marks, SUM(b.marks) AS [Cumulative Sum]
from cte a
left join cte b on a.studid = b.studid AND b.rownum <= a.rownum
group by a.studid, a.rownum, a.subcode, a.marks
order by a.studid, a.subcode
Cumulative Sum Output

Refer related post to calculate cumulative sum using recursive CTE,
Running total in SQL Server

Refer related post for SQL Server 2012,
Cumulative Sum in SQL Server 2012